Answer:
[tex]\boxed{x=\frac{4\pm\sqrt{2}}{2}}[/tex]
Step-by-step explanation:
Part 1: Rewriting equation to match ax² + bx + c = 0 (quadratic function)
The given equation is not written in quadratic form. To rewrite the equation:
To overcome this difficulty, follow these mathematical steps:
[tex]2x^2=8x-7\\2x^2-8x=-7\\2x^2-8x+7=0[/tex]
Subtract 8x from both sides of the equation to rearrange it to the left side. Then, add 7 to rearrange it as well. Finally, set the three values on the left of the equation equal to zero.
Part 2: Using the quadratic formula
The quadratic formula is defined as [tex]\boxed{x=\frac{-b\pm\sqrt{b^2-4ac} }{2a} }[/tex].
Using the parent quadratic function, the values are easy to find in the given equation. [tex]\boxed{a=2, b=-8, c=7}[/tex]
Substitute these values into the quadratic formula and solve for x.
[tex]x=\frac{8\pm\sqrt{(-8)^2-4(2)(7)}}{2(2)} \\\\x=\frac{8\pm\sqrt{64-4(14)}}{4}\\\\x=\frac{8\pm\sqrt{64-56}}{4} \\\\x=\frac{8\pm\sqrt{8}}{4}\\\\x= 2\pm\frac{\sqrt{8}}{4}\\ \\x=2\pm\frac{\sqrt{2}}{2}[/tex]
Part 3: Solving for x with the values from the quadratic formula
Now that x is set equal to the simplified version of the equation, the operations have to be followed through with.
This equation will have two zeros/roots to solve for by setting x equal to zero.
Operation 1: Addition
[tex]x=2+\frac{\sqrt{2} }{2}\\\\x=\frac{4+\sqrt{2}}{2}[/tex]
Operation 2: Subtraction
[tex]x=2-\frac{\sqrt{2}}{2}\\ \\x=\frac{4-\sqrt{2}}{2}[/tex]
Because both values are the exact same (minus the operations), the roots can be simplified even further to one value:
[tex]\boxed{x=\frac{4\pm\sqrt{2}}{2}}[/tex]
