Answer: m = -5
Step-by-step explanation:
[tex]\dfrac{m+3}{m^2+4m+3}-\dfrac{3}{m^2+6m+9}=\dfrac{m-3}{m^2+4m+3}\\\\\\\dfrac{m+3}{(m+3)(m+1)}-\dfrac{3}{(m+3)(m+3)}=\dfrac{m-3}{(m+3)(m+1)}\quad \rightarrow m\neq-3, m\neq-1[/tex]
Multiply by the LCD (m+3)(m+3)(m+1) to eliminate the denominator. The result is:
(m + 3)(m + 3) - 3(m + 1) = (m - 3)(m - 3)
Multiply binomials, add like terms, and solve for m:
(m² + 6m + 9) - (3m + 3) = m² - 9
m² + 6m + 9 - 3m - 3 = m² - 9
m² + 3m + 6 = m² - 9
3m + 6 = -9
3m = -15
m = -5
