Answer:
[tex]\large \boxed{\sf \bf \ \ \text{The solutions are }(2,4) \text{ and } (-2,-4) \ \ }[/tex]
Step-by-step explanation:
Hello, this is the same kind of question that you have already posted( brainly.com/question/17141820).
I would suggest that you check my previous answer and try to apply the same logic here. When you try it if you have any question please let me know. It will be the more efficient way for you to learn how to solve it by yourself.
As I have already provided details for the previous question I will be more succinct here.
Again we can write y = y and then we have to solve the following.
[tex](x+1)^2-5=2x\\\\x^2+2x+1^2-5-2x=0\\\\x^2-4=x^2-2^2=(x-2)(x+2)=0\\\\x=2 \ \ or \ \ x=-2[/tex]
The solutions are (2,4) and (-2,-4)
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
