contestada

A particular geometric sequence has strictly decreasing terms. After the first term, each successive term is calculated by multiplying the previous term by $\frac{m}{7}$. If the first term of the sequence is positive, how many possible integer values are there for $m$?

Respuesta :

Answer:

6 possible integers

Step-by-step explanation:

Given

A decreasing geometric sequence

[tex]Ratio = \frac{m}{7}[/tex]

Required

Determine the possible integer values of m

Assume the first term of the sequence to be positive integer x;

The next sequence will be [tex]x * \frac{m}{7}[/tex]

The next will be; [tex]x * (\frac{m}{7})^2[/tex]

The nth term will be [tex]x * (\frac{m}{7})^{n-1}[/tex]

For each of the successive terms to be less than the previous term;

then [tex]\frac{m}{7}[/tex] must be a proper fraction;

This implies that:

[tex]0 < m < 7[/tex]

Where 7 is the denominator

The sets of [tex]0 < m < 7[/tex] is [tex]\{1,2,3,4,5,6\}[/tex] and their are 6 items in this set

Hence, there are 6 possible integer