Answer:
[tex]P(Brown\ or\ Green) = \frac{13}{25}[/tex]
Step-by-step explanation:
Given
[tex]n(Brown) = 20[/tex]
[tex]n(Green) = 6[/tex]
[tex]n(Blue) = 17[/tex]
[tex]n(Hazel) = 7[/tex]
Required
Determine the probability of Brown or Green eyes
First, the total number of respondents have to be calculated;
[tex]Total = 20 + 6 + 7 + 17[/tex]
[tex]Total = 50[/tex]
The events described above is a mutually exclusive event and as such, the required probability will be calculated by;
[tex]P(Brown\ or\ Green) = P(Brown) + P(Green)[/tex]
Calculating P(Brown)
[tex]P(Brown) = \frac{n(Brown)}{Total}[/tex]
Substitute 20 for n(Brown) and 50 for Total
[tex]P(Brown) = \frac{20}{50}[/tex]
Calculating P(Green)
[tex]P(Green) = \frac{n(Green)}{Total}[/tex]
Substitute 6 for n(Green) and 50 for Total
[tex]P(Green) = \frac{6}{50}[/tex]
So;
[tex]P(Brown\ or\ Green) = P(Brown) + P(Green)[/tex]
[tex]P(Brown\ or\ Green) = \frac{20}{50} + \frac{6}{20}[/tex]
Take LCM
[tex]P(Brown\ or\ Green) = \frac{20+6}{50}[/tex]
[tex]P(Brown\ or\ Green) = \frac{26}{50}[/tex]
Divide the numerator and denominator by 2
[tex]P(Brown\ or\ Green) = \frac{13}{25}[/tex]
Answer:
13/25
Step-by-step explanation:
Total number of people = 50
Probability of choosing a person with brown eyes [P(A)] = 20/50
Probability of choosing a person with green eyes [P(B)] = 6/50
Using the addition rule of mutual exclusive events (since they have specified brown OR blue, we use this formula):
P(A U B) = P(A) + P(B)
=> P(A U B) = 20/50 + 6/50 = 26/50 = 13/25
Therefore the probability of a person choosing a group that has brown or green eyes = 13/25
Also I got it right on edge haha, if you're still worried!!!!!!!!
Hope this helps :))))))))))))))
