Answer:
[tex]\Large \boxed{-\dfrac{5}{4}(x+3)(x+1)(x-2)}[/tex]
Step-by-step explanation:
Hello,
Based on the indication, we can write this polynomial as below, k being a real number that we will have to identify (degree = 3 and we have three zeroes -3, -1, and 2).
[tex]\Large \boxed{k(x+3)(x+1)(x-2)}[/tex]
We know that the point (1,10) is on the graph of this function, so we can say.
[tex]k(1+3)(1+1)(1-2)=10}\\\\4*2*(-1)*k=10\\\\-8k=10\\\\k=\dfrac{10}{-8}=-\dfrac{5}{4}[/tex]
Then the solution is:
[tex]\large \boxed{-\dfrac{5}{4}(x+3)(x+1)(x-2)}[/tex]
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
