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Is the following Triangle a right triangle If, Not what type of triangle (acute or obtuse) is it? Show your work! 3,4,6

Respuesta :

Answer:

[tex]\boxed{\sf Obtuse \ Angled \ Triangle}[/tex]

Explanation:

Let's check it by Pythagorean theorem:

[tex]\sf c^2 = a^2+b^2[/tex]

Where c = 6, a = 4 and b = 3

[tex]\sf (6)^2= (4)^2+(3)^2[/tex]

[tex]\sf 36 = 16+9[/tex]

[tex]36 \neq 25[/tex]

But,

[tex]\sf 36> 25[/tex]

When [tex]\sf c^2 > a^2+b^2[/tex], then the triangle is obtuse angled triangle.

Answer:

[tex]\boxed{ \sf Obtuse \ triangle}[/tex]

Explanation:

We can check if the triangle is a right triangle or not by using Pythagorean theorem.

[tex]c=\sqrt{a^2 +b^2 }[/tex]

[tex]6=\sqrt{3^2 +4^2 }[/tex]

[tex]6=\sqrt{9+16 }[/tex]

[tex]6=\sqrt{25 }[/tex]

[tex]6=5[/tex]

The triangle is not a right triangle.

When [tex]c>\sqrt{a^2 +b^2 }[/tex], the triangle is an obtuse triangle.