Answer:
(A) [tex]y = x+3[/tex]
Step-by-step explanation:
Using the values of (-6, -3), (3,6), and (5,8) we can substitute the values into each equation and see if the equation meets the requirements for all 3.
Let's test A first.
[tex]-3 = -6+3[/tex]
Correct, let's try the second pair.
[tex]6 = 3+3[/tex]
Correct, let's try the third pair.
[tex]8 = 5+3[/tex]
So yes, this equation works.
For fun, let's try the other equations.
Let's test B.
[tex]-3 = -6-3[/tex]
This is not true as -6 -3 = -9. So this equation is immediately ruled out.
Let's test C.
[tex]-3 = 2\cdot-6[/tex]
Again this doesn't work, as -6 times 2 is -12. So this equation is also ruled out.
Let's try D.
[tex]-3 = \frac{1}{2}\cdot-6[/tex]
This works, as half of -6 is -3 - however the equation will only work if all 3 pairs work for it.
Let's try the second pair.
[tex]6 = \frac{1}{2}\cdot3[/tex]
This doesn't work, as half of 3 is 1.5. This equation is also ruled out.
Therefore, A is the only equation that works with these pairs.
Hope this helped!
