Answer:
1. [tex]c = \sqrt{2}[/tex].
2. b = 4.
Step-by-step explanation:
To solve these two questions, keep the Pythagorean Theorem in mind: [tex]a^2 + b^2 = c^2[/tex]. Also remember that measurements cannot be negative, so we will disregard the negative answers.
1. a = 1, and b = 1. c = ?
[tex]1^2 + 1^2 = c^2[/tex]
[tex]1 + 1 = c^2\\[/tex]
[tex]c^2 = 1 + 1\\c^2 = 2\\\sqrt{c^2} = \sqrt{2}\\c = \sqrt{2}[/tex]
2. a = 3, c = 5. b = ?
[tex]3^2 + b^2 = 5^2\\9 + b^2 = 25\\b^2 = 16\\\sqrt{b^2} = \sqrt{16}\\b = 4[/tex]
Hope this helps!
