Answer:
The least possible price is p = £110
Step-by-step explanation:
From the question we are told that
The number of bracelets to be made is [tex]n = 150[/tex]
The length of silver require for on bracelet is [tex]x = 26 \ cm = 0.26 \ m[/tex]
The option of silver length packs that she buys is a = 10.5 m packs
b = 3.7 m packs
Generally
1 bracelet [tex]\to[/tex] 0.26 m
150 bracelet [tex]\to[/tex] z
=> [tex]z = \frac{150 * 0.26}{1}[/tex]
=> [tex]z = 39 \ m[/tex]
Now for option a i.e 10.5 m per pack
The number of packs require is
[tex]v = \frac{z}{a}[/tex]
=> [tex]v = \frac{39}{ 10.5}[/tex]
=> [tex]v = 3.7 1[/tex]
given that the number of packs cannot be a fraction but an integer hence she needs to purchase v = 4
and that 4 packs would equal t = 4 * 10.5 = 42 meters of silver
Now for option d i.e 3.7 meters per pack
The number of packs requires is
[tex]w = \frac{z}{b}[/tex]
=> [tex]w = \frac{39}{3.7}[/tex]
=> [tex]w = 10.54[/tex]
given that the number of packs cannot be a fraction but an integer hence she needs to purchase w= 11
and that 11 packs would equal t = 11 * 3.7 = 40.7 meters of silver
So the comparing the option and option b we see that for her to pay as little as possible she needs to go for option b since option be will produce the 150 bracelet with a little excess while option a will produce the 150 bracelet with much excess
Assuming the price for the 3.7 m pack is £10
And the price for the 10.7 pack is £30
The least possible amount she would pay is
[tex]p = 10 * 11[/tex]
p = £110
