Draw the image of ABC under dilation whose center is P and scale factor is 4.

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eudora eudora · Answer 1 · 2020-08-10T13:47:56+02:00

Answer:

Step-by-step explanation:

Let the point P is origin (0, 0), segment AB lies on the x-axis and segment PC on the y-axis,

Coordinates of A, B and C will be (1, 0), (2, 0) and (0, 2).

When triangle ABC is dilated by a scale factor 4 about the origin,

Rule for dilation;

(x, y) → (4x, 4y)

New coordinates of the points A, B and C will be,

A(1, 0) → A'(4, 0)

B(-2, 0) → B'(-8, 0)

C(0, 2) → C'(0, 8)

By plotting points A', B' and C' we can get the dilated image A'B'C'.

MrRoyal MrRoyal · Answer 2 · 2022-01-25T14:07:23+01:00

Dilation involves changing the size of a shape.

Assume point P is the center of origin, then we have the following coordinates of ABC

[tex]A = (1,0)[/tex]

[tex]B = (-2,0)[/tex]

[tex]C = (0,2)[/tex]

The scale factor (k) is given as:

[tex]k= 4[/tex]

So, the dilation rule is represented as:

[tex](x,y) \to (4 \times (x,y)[/tex]

Using the above dilation rule, the following coordinates represent the image of triangle ABC

[tex]A' = (4,0)[/tex]

[tex]B' = (-8,0)[/tex]

[tex]C = (0,8)[/tex]

See attachment for the image of the dilation.