Answer:
[tex]\Large \boxed{\sf \bf \ \ 2(x-4)^3(x+2)^2 \ \ }[/tex]
Step-by-step explanation:
Hello, please consider the following.
Construct a polynomial function with the following properties...
... fifth degree
It means that the polynomial can be written as below.
[tex]a_5x^5+a_4x^4+a_3x^3+a_2x^2+a_1x+a_0 \ \text{ with }a_5\text{ different from 0}\\\\\text{ or } k(x-x_1)(x-x_2)(x-x_3)(x-x_4)(x-x_5) \\\\ \text{ with k different from 0 and } (x_i)_{1\leqi\leq 5 } \text { are the roots.}[/tex]
... 4 is a zero of multiplicity 3
We can write the polynomial as below.
[tex]k(x-4)(x-4)(x-4)(x-x_4)(x-x_5)=k(x-4)^3(x-x_4)(x-x_5)[/tex]
... −2 is the only other zero
Because this is the only other zero, we can deduce that -2 is a zero of multiplicity 2.
[tex]k(x-4)(x-4)(x-4)(x-x_4)(x-x_5)\\\\=k(x-4)^3(x-(-2))(x-(-2))\\\\=k(x-4)^3(x+2)^2[/tex]
... leading coefficient is 2.
Finally, it means that k = 2 and then the polynomial function is:
[tex]\large \boxed{2(x-4)^3(x+2)^2}[/tex]
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
