Answer:
The answer to your question is given below.
Explanation:
The reaction of sulfuric acid and potassium hydroxide is called neutralisation.
Neutralisation is a reaction involving an acid and a base which produces salt and water only.
For the react between sulfuric acid, H2SO4 and potassium hydroxide, KOH, we can predict the products obtained as follow:
H2SO4 + KOH —>
In solution, H2SO4 and KOH will dissociate as follow:
H2SO4(aq) —> 2H^+(aq) + SO4^2-(aq)
KOH(aq) —> K^+(aq) + OH^-(aq)
H2SO4 + KOH —>
2H^+(aq) + SO4^2-(aq) + K^+(aq) + OH^-(aq) —> K^+(aq) + SO4^2-(aq) + 2H^+(aq) + OH^-
H2SO4 + KOH —> K2SO4 + H2O
Now, we can balance the above equation as follow:
H2SO4 + KOH —> K2SO4 + H2O
There are 2 atoms K on right side and 1 atom on the left side. It can be balance by writing 2 in front of ko as shown below:
H2SO4 + 2KOH —> K2SO4 + H2O
There are 2 atoms of H on the right side and a total of 4 atoms on the left side. It can be balance by writing 2 in front of H2O as shown below:
H2SO4 + 2KOH —> K2SO4 + 2H2O
Now,the equation is balanced.
Answer:
Given the reactants, H2SO4 and KOH, we are asked to determine the product(s) of the reaction. Since H2SO4 is an acid and KOH is a base. This is a neutralization reaction, thus, the products are salt and water.
So, H+ from H2SO4 will react with OH- from KOH forming H2O. K+ will also react with SO4 2- forming K2SO4. Therefore, the balanced reaction will be:
H2SO4 + 2KOH ---> K2SO4 + 2H2O
Explanation:
