Answer:
9.39x10⁻³M NH₄⁺
Explanation:
To find molarity of NH₄⁺ we need to calculate moles of NH₄⁺ that comes from NH₄NO₃ and (NH₄)₃PO₄
Moles from NH₄NO₃ (Molar mass: 80.043g/mol):
5.66g * (1mol / 80.043g) = 0.0707 moles NH₄NO₃ = Moles NH₄⁺
Moles from (NH₄)₃PO₄ (Molar mass: 149.09g/mol):
4.42g * (1mol / 149.09g) = 0.0296 moles (NH₄)₃PO₄ * 3 = 0.0889 moles NH₄⁺
Total moles NH₄⁺:
0.0707 moles + 0.0889 moles = 0.1596 moles NH₄⁺ in 17.0L
Molarity: 0.1596 moles / 17.0L =
