Answer:
Explanation:
1 )
F = k q₁q₂ / r² where k = 9 x 10⁹
So force F₁ = [tex]\frac{kq_1q_2}{(\frac{r}{2}+\frac{\sqrt{9} r}{2})^2 }[/tex]
= [tex]\frac{kq_1q_2}{(\frac{r}{2}+\frac{3 r}{2} )^2 }[/tex]
= k q₁q₂ /4 r²
F₁ = F / 4
2 ) Electric field due to charge density σ
= σ / ε₀
So net electric field between the plates
= ( σ₁ - σ₂ ) / ε₀
Force on charge q
= ( σ₁ - σ₂ ) q / ε₀
work done = force x displacement
= ( σ₁ - σ₂ ) x q x d / ε₀
