Answer:
[tex] \boxed{ \bold{ \sf{ width \: of \: a \: rectangle = 5.5 \: inches}}}[/tex]
[tex] \boxed{ \bold{ \sf{length \: of \: a \: rectangle =8.5 \ \: \: inches}}}[/tex]
Step-by-step explanation:
Let the width of a rectangle be 'w'
Length of a rectangle = w + 3
Perimeter of a rectangle = 28 inches
To find : dimensions of the rectangle ( length and width )
Finding the width of a rectangle ( w )
[tex] \boxed{ \sf{perimeter \: of \: a \: rectangle = 2(l + w)}}[/tex]
[tex] \dashrightarrow{ \sf{28 = 2(w + 3 + w)}}[/tex]
[tex] \dashrightarrow{ \sf{28 = 2(2w + 3)}}[/tex]
[tex] \dashrightarrow{ \sf{28 = 4w + 6}}[/tex]
[tex] \dashrightarrow{ \sf{4w + 6 = 28}}[/tex]
[tex] \dashrightarrow{ \sf{4w = 28 - 6}}[/tex]
[tex] \dashrightarrow{ \sf{4w = 22}}[/tex]
[tex] \dashrightarrow{ \sf{ \frac{4w}{4} = \frac{22}{4} }}[/tex]
[tex] \dashrightarrow{ \sf{w = 5.5 \: inches}}[/tex]
Width of a rectangle = 5.5 inches
Now, replacing / substituting the value of w in order to find the length of a rectangle
[tex] \sf{ length = 3 + w}[/tex]
[tex] \dashrightarrow{ \sf{length = 3 + 5.5}}[/tex]
[tex] \dashrightarrow{ \sf{length = 8.5 \: \: inches}}[/tex]
Length of a rectangle = 8.5 inches
Hope I helped!
Best regards! :D
