Answer:
The number of hours Moran wold have driven before Andre catches up with him is 14 hours
Step-by-step explanation:
The given information are;
The speed with which Andre will drive = 70 miles per hour
The speed with which Morgan will drive = 55 miles per hour
The time of departure of Morgan = 3 hours before Andre departs
Let the time at which Andre catches up with Morgan be, t
We have, from the definition of distance traveled;
Distance traveled =Speed × Time
The distance Morgan would have driven in t hours = 55 × t
Given that to catch up with Morgan, Andre has to travel the same distance, and that Andre starts 3 hours late, we have;
The distance Andre would drive when Morgan has driven for t hours = 70 × (t - 3)
Therefore, since the distance at the point they meet is the same distance for them both, we have;
55 × t = 70 × (t - 3)
55 × t = 70 × t - 210
210 = 70 × t - 55 × t = 15 × t
t = 210/15 = 14 hours
Therefore, Morgan would have driven for 14 hours before Andre catches uo with him.
Answer:
Morgan walks 2 miles per hour.
Step-by-step explanation:
took the test. ;)
