1 liter is equivalent to a volume of 1000 cm3 (the same as 10 cm x 10 cm x 10 cm). If a beaker has a cross-section the size of the circle below, and a height of 10 cm, what is its volume

Respuesta :

Answer:

[tex]Volume = \frac{220}{7}r^2[/tex]

Step-by-step explanation:

Given

Height = 10cm

See Attachment for complete question

Required

Determine the volume of the circle

The volume is calculated as thus;

[tex]Volume = \pi r^2h[/tex]

Take [tex]\pi[/tex] as [tex]\frac{22}{7}[/tex]

So; Volume becomes

[tex]Volume = \frac{22}{7} * r^2 * h[/tex]

Substitute 10 for h

[tex]Volume = \frac{22}{7} * r^2 * 10[/tex]

[tex]Volume = \frac{220}{7} * r^2[/tex]

Since, the value of the radius is not given;

The volume of the circle is:

[tex]Volume = \frac{220}{7}r^2[/tex]

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