Answer:
[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{10 \: N}}}}}[/tex]
Step-by-step explanation:
Given,
Load distance ( LD ) = 2m
Load ( L ) = 800 N
Effort distance ( ED ) = 160 m
Effort ( E ) = ?
Finding the Effort applied
Apply the principal of simple machine :
[tex] \boxed{ \sf{L \times LD = E\times ED}}[/tex]
[tex] \longrightarrow{ \sf{800 \times 2 = E \times 160}}[/tex]
[tex] \longrightarrow{ \sf{1600 = 160 \: E}}[/tex]
[tex] \longrightarrow{ \sf{160E = 1600}}[/tex]
[tex] \longrightarrow{ \sf{ \frac{160E}{160} = \frac{1600}{160} }}[/tex]
[tex] \longrightarrow{ \sf{E = 10 \: \: newton}}[/tex]
Effort applied = 10 N
Hope I helped!
Best regards! :D
