contestada

Calculate the molar free energy of combustion for liquid n-octane, C8H18 with the given data: AG'CH,,!) 6.4 kJ/mol AG®(00,,8) -394.4 kJ/mol AGʻ(H,0,8) -228.57 kJ/mol a. -5218.7 kJ/mol b. -5384.6 kJ/mol c. -629.4 kJ/mol d. +629.4 kJ/mol e. -2609.4 kJ/mol

Respuesta :

sebassandin

Answer:

a. -5218.7 kJ/mol

Explanation:

Hello,

In this case, the combustion of liquid n-octane is represented by:

[tex]C_8H_{18}(l)+\frac{25}{2} O_2(g)\rightarrow 8CO_2(g)+9H_2O(g)[/tex]

Thus, the molar free energy of combustion (reaction) is:

[tex]\Delta _CH=8*\Delta _fH_{CO_2}+9*\Delta _fH_{H_2O}-\Delta _fH_{C_8H_{18}}[/tex]

Hence, with the given data we obtain:

[tex]\Delta _CH=8*(-394.4kJ/mol)+9*\Delta _fH_{-228.57kJ/mol}-6.4kJ/mol\\\\\Delta _CH=-5218.73kJ/mol[/tex]

Therefore, answer is a. -52 kJ/mol18.7.

Regards.

pstnonsonjoku

The heat of combustion is  -5218.7 kJ/mol.

The molar free energy of the reaction can be obtained as the sum of the free energy of the products minus the sum of the free energy of the reactants.

Now the reaction is;

C8H18(g) + 25/2O2(g) ----> 8CO2(g) + 9H2O(l)

Hence;

ΔGreaction = [8( -394.4) + 9(-228.57)] - [ 6.4  + 0]

=[(-3155.2) + (-2057.13)] - 6.4

=  -5218.7 kJ/mol

Learn more about heat of combustion: https://brainly.com/question/1195122

Otras preguntas