Answer:
This is the answer
Step-by-step explanation:
Solving 3x2-9x-5 = 0 by the Quadratic Formula .
According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
x = ————————
2A
In our case, A = 3
B = -9
C = -5
Accordingly, B2 - 4AC =
81 - (-60) =
141
Applying the quadratic formula :
9 ± √ 141
x = —————
6
√ 141 , rounded to 4 decimal digits, is 11.8743
So now we are looking at:
x = ( 9 ± 11.874 ) / 6
Two real solutions:
x =(9+√141)/6=3/2+1/6√ 141 = 3.479
or:
x =(9-√141)/6=3/2-1/6√ 141 = -0.479
Two solutions were found :
x =(9-√141)/6=3/2-1/6√ 141 = -0.479
x =(9+√141)/6=3/2+1/6√ 141 = 3.479
