Answer:
the Balogna could carry 19 passengers if filled with Hydrogen.
the Balogna could carry 17 passengers if filled with Helium.
Explanation:
Given that:
the radius of the cylinder r = 4.0 cm
the height h = 40 m
the volume of the cylinder will be:
[tex]V = \pi r^2 h[/tex]
V = π (4.0 m)² (40)
V = 2010.62 m³.
where the density of the air = 1.23 kg/m³
the mass of the displaced air = Volume V ×density of the air
= 2010.62 m³ × 1.23 kg/m³
= 2473.0626 kg
To calculate how many passengers the Balogna could carry if it were filled with hydrogen, we have the following:
We are given the density of H₂ to be = 0.090 kg/m³
Therefore, the mass of Helium in the balloon = Volume V × density of the hydrogen
= 2010.62 m³ × 0.090 kg/m³
= 180.9558 kg
The total mass of the balloon = mass of H₂ + mass of empty balloon.
The total mass of the balloon = (180.9558+ 750) kg
= 930.9558 kg
Now, the Mass difference = mass of the air displaced -total mass of the balloon.
the Mass difference = (2473.0626 - 930.9558 ) kg
the Mass difference = 1542.1068 kg
∴
number of persons = mass difference/ mass of passenger
the number of persons = 1542.1068 kg /80 (kg/person)
the number of persons = 19.27 persons
the number of passengers [tex]\simeq[/tex] 19 passengers.
To calculate how many passengers the Balogna could carry if it were filled with helium, we have the following:
We are given the density of Helium to be = 0.18 kg/m³
Therefore, the mass of Helium in the balloon = Volume V × density of the hydrogen
= 2010.62 m³ × 0.18 kg/m³
= 361.9116 kg
The total mass of the balloon = mass of Helium + mass of empty balloon.
The total mass of the balloon = (361.9116 + 750) kg
= 1111.9116 kg
Now, the Mass difference = mass of the air displaced -total mass of the balloon.
the Mass difference = (2473.0626 - 1111.9116 ) kg
the Mass difference = 1361.151 kg
∴
number of persons = mass difference/ mass of passenger
the number of persons = 1361.151 kg /80 (kg/person)
the number of persons = 17.01 persons
the number of passengers [tex]\simeq[/tex] 17 passengers.
