Answer:
The test statistics is [tex]t = -1.727[/tex]
Step-by-step explanation:
From the question we are told that
The data given is
330 620 1870 2410 4620 6396 7822 81028309 12882 14419 16092 18384 20916 23812 25814
The population mean is [tex]\mu = 14400[/tex]
The sample size is n = 16
The null hypothesis is [tex]\mu \le 14400[/tex]
The alternative hypothesis is [tex]H_a : \mu > 14400[/tex]
The sample mean is mathematically evaluated as
[tex]\= x = \frac{\sum x_i}{n}[/tex]
So
[tex]\= x = \frac{330+ 620+ 1870 +2410+ 4620+ 6396+ 7822+ 8102+8309+ 12882+ 14419+ 16092+ 18384 +20916+ 23812+ 25814 }{16}[/tex]
=> [tex]\= x = 10799.9[/tex]
The standard deviation is mathematically represented as
[tex]\sigma =\sqrt{\frac{ \sum (x_i - \=x)^2}{n}} [/tex]
So
[tex]\sigma =\sqrt{\frac{(330- 10799.9)^2 + (620- 10799.9)^2+ (1870- 10799.9)^2 +(2410- 10799.9)^2 + (4620- 10799.9)^2 +(6396- 10799.9)^2 +(7822- 10799.9)^2 }{16}} \ ..[/tex]
[tex]..\sqrt{ \frac{(8102 - 10799.9)^2 +(8309 - 10799.9)^2 + (12882 - 10799.9)^2 + (14419 - 10799.9)^2 + (16092 - 10799.9)^2 + (18384 - 10799.9)^2 +(20916 - 10799.9)^2 }{16}} \ ...[/tex]
[tex]\ ... \sqrt{\frac{(23812 - 10799.9)^2 +(25814 - 10799.9)^2 }{16}}[/tex]
=> [tex]\sigma = 8340[/tex]
Generally the test statistic is mathematically represented as
[tex]t = \frac{10799.9- 14400}{ \frac{8340}{\sqrt{16} } }[/tex]
[tex]t = -1.727[/tex]
From the z-table the p-value is
[tex]p-value = P(Z > t) = P(Z > -1.727) = 0.95792[/tex]
From the values obtained we see that
[tex]p-value > \alpha[/tex] so we fail to reject the null hypothesis
Which implies that the claim of the NarStor is wrong
