Answer/Step-by-step explanation:
Line segment AB consists of segment AC and segment CB.
AC = 7 cm
CB = 21 cm
The entire segment, AB = 21 + 7 = 28cm
The ratio of the segments partitions can be stated as follows:
Ratio of AC to CB = AC:CB = 7:21 = 1:3 = [tex] \frac{1}{3} [/tex]
AC is ¼ of AB [tex] (\frac{1}{1 + 3} = \frac{1}{4}) [/tex]
CB is ¾ of AB [tex] (\frac{3}{1 + 3} = \frac{3}{4}) [/tex]
