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The path of water from a hose on a fire tugboat can be approximated by the equation y=-0.0055x^2 +1.15x + 5, where y is the height above the ocean and x is the distance from the tugboat. When the water is 6 ft above the ocean how far is it from the tugboat

Respuesta :

tochinwachukwu33

Answer:

The water is 208.22ft from the tug boat

Step-by-step explanation:

The governing equation is [tex]y=-0.0055x^2 +1.15x + 5[/tex]

y is the height above the ocean

x is the distance from the tugboat

if y= 6ft, the equation will now become

[tex]6=-0.0055x^2 +1.15x + 5[/tex]

we can arrange this properly to form a quadratic equation by grouping like terms.

[tex]-0.0055x^2 +1.15x -1=0[/tex]

solving quadratically we have two values of x as  208.22ft and 0.873 ft.

We can take a more realistic value as a solution to our problems:

208.22ft

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