Answer:
[tex] \boxed{\sf Acceleration \ of \ the \ car = -5 \ m/s^2} [/tex]
Given:
Initial speed (u) = 30 m/s
Final speed (v) = 20 m/s
Time taken (t) = 2s
To Find:
Acceleration (a) of the car
Explanation:
From equation of motion we have:
[tex] \boxed{ \bold{v = u + at}}[/tex]
By substituting value of v, u & t in the equation we get:
[tex]\sf \implies 20 = 30 + a(2) \\ \\ \sf \implies 2a + 30 = 20 \\ \\ \sf \implies 2a = 20 - 30 \\ \\ \sf \implies 2a = - 10 \\ \\ \sf \implies a = - \frac{10}{2} \\ \\ \sf \implies a = - 5 \: m {s}^{ - 2} [/tex]
[tex] \therefore[/tex]
Acceleration (a) of the car = -5 m/s²
