Please solve these problems. 2(2x-1)=3(x-6) and 4(5-7b)-4=-3(1+3b) I will pick Brainliest, and award 15 points. (They are separate problems tho)

Respuesta :

Answer:

see explanation

Step-by-step explanation:

Given

2(2x - 1) = 3(x - 6) ← distribute parenthesis on both sides

4x - 2 = 3x - 18 ( subtract 3x from both sides )

x - 2 = - 18 ( add 2 to both sides )

x = - 16

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Given

4(5 - 7b)- 4 = - 3(1 + 3b) ← distribute parenthesis on both sides )

20 - 28b - 4 = - 3 - 9b , that is

16 - 28b = - 3 - 9b ( add 9b to both sides )

16 - 19b = - 3 ( subtract 16 from both sides )

- 19b = - 19 ( divide both sides by - 19 )

b = 1

Answer:

[tex]\sf 1) \ \ \ \ \huge\boxed{\sf x = - 16}[/tex]

[tex]\sf 2) \ \ \ \ \huge\boxed{\sf b = 1}[/tex]

Step-by-step explanation:

[tex]\sf 1) \ 2(2x-1) = 3(x-6)\\\\Resolving \ Parenthesis\\\\4x - 2 = 3x -18\\\\Combining \ like \ terms\\\\4x-3x = -18+2\\\\x = -16[/tex]

[tex]\rule[225]{225}{2}[/tex]

[tex]\sf 2) \ 4(5-7b) - 4 = -3(1+3b)\\\\Resolving\ Parenthesis\\\\20 - 28b-4 = -3-9b\\\\16 - 28b = -3-9b\\\\Combining \ like \ terms\\\\16+3 = -9b + 28b\\\\19 = 19b\\\\Dividing \ both \ sides \ by \ 19\\\\1 = b \\\\OR\\\\b = 1[/tex]

[tex]\rule[225]{225}{2}[/tex]