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Answer:
Tim's bean sprout grow by more than [tex]\frac{5}{8} \text{ inches}[/tex].
Step-by-step explanation:
We are given that Tim's bean sprout grew 3 3/8 inches. Teegan's bean sprout grew 2 3/4 inches.
We have to find how many more inches did Tim's bean sprout grow than Teegan's.
Firstly, converting both the mixed fractions in improper fraction get;
Tim's bean sprout grew = [tex]3\frac{3}{8}[/tex] = [tex]\frac{27}{8} \text{ inches}[/tex]
Teegan's bean sprout grew = [tex]2\frac{3}{4}[/tex] = [tex]\frac{11}{4} \text{ inches}[/tex]
Since the denominator of both the fractions is not the same, so we can't compare them both as which is larger or smaller.
Tim's bean sprout grew = [tex]\frac{27\times 1}{8\times 1} = \frac{27}{8} \text{ inches}[/tex]
Teegan's bean sprout grew = [tex]\frac{11 \times 2}{4\times 2}=\frac{22}{8} \text{ inches}[/tex]
Now, we can clearly see that Tim's bean sprout grew more than Teegan's bean sprout.
So, Tim's bean sprout grow by more than = [tex]\frac{27}{8}- \frac{22}{8}[/tex] = [tex]\frac{5}{8} \text{ inches}[/tex]
Hence, Tim's bean sprout grow by more than [tex]\frac{5}{8} \text{ inches}[/tex].
Answer:
Tim's bean sprout grow by more than .5/8th inches
Step-by-step explanation:
