The area of a rectangular wall of a barn is 216 square feet. Its length is 6 feet longer than twice its width. Find the length and width of the wall of the barn

Respuesta :

Answer:

Length is 24 feet and width is 9 feet.

Step-by-step explanation:

It is given that length of a rectangular wall is 6 feet longer than twice its width.

Let x feet be the width of wall.

Length = 2x+6 feet

Area of rectangle is

[tex]A=length \times width[/tex]

[tex]A=(2x+6)\times x[/tex]

[tex]A=2x^2+6x[/tex]

It is given that area of a rectangular wall of a barn is 216 square feet.

[tex]2x^2+6x=216[/tex]

[tex]x^2+3x=108[/tex]

[tex]x^2+3x-108=0[/tex]

Splitting the middle term, we get

[tex]x^2+12x-9x-108=0[/tex]

[tex]x(x+12)-9(x+12)=0[/tex]

[tex](x+12)(x-9)[/tex]

[tex]x=-12,9[/tex]

Width can not be negative. So width is 9 feet.

Length [tex]=2(9)+6=18+6=24\text{ feet}[/tex]

Therefore, length is 24 feet and width is 9 feet.