Respuesta :

Answer:  1) 65°     2) 17°   3) 53°  or  37°

Step-by-step explanation:

[tex]1.\quad \cos \theta=\dfrac{adjacent}{hypotenuse}\\\\\\.\quad \quad \cos \theta=\dfrac{3}{7}\\\\\\.\qquad \qquad \theta=\cos ^{-1}\bigg(\dfrac{3}{7}\bigg)\\\\\\.\qquad \qquad \theta =65^o[/tex]

[tex]2.\quad \tan \theta =\dfrac{opposite}{adjacent}\\\\\\.\quad \quad \tan\theta =\dfrac{8}{26}\\\\\\.\qquad \qquad \theta =\tan ^{-1}\bigg(\dfrac{4}{13}\bigg)\\\\\\.\qquad \qquad \theta = 17^o[/tex]

3.  Which angle do you need? I solved for both:

               Bottom Right                     Top Left

[tex].\qquad \cos \theta=\dfrac{adjacent}{hypotenuse}\qquad \qquad \sin \theta = \dfrac{opposite}{hypotenuse}\\\\\\.\quad \quad \cos \theta=\dfrac{14}{23}\qquad \qquad \qquad \qquad \sin \theta=\dfrac{14}{23}\\\\\\.\qquad \qquad \theta=\cos ^{-1}\bigg(\dfrac{14}{23}\bigg)\qquad \qquad \quad \theta=\sin ^{-1}\bigg(\dfrac{14}{23}\bigg)\\\\\\.\qquad \qquad \theta =53^o\qquad \qquad \qquad \qquad \quad \theta =37^o[/tex]

Wolfyy

Question 1:

cosθ = adj/hyp

cosθ = 3/7

θ = cos^-1(3/7)

θ = 65

Questions 2:

tanθ = opp/adj

tanθ = 8/26

θ = tan^-1(4/13)

θ = 17

Question 3:

Top left:

sinθ = opp/hyp

sinθ = 14/23

θ = tan^-1(14/23)

θ = 37

Bottom Right:

cosθ = adj/hyp

cosθ = 14/23

θ = cos^-1(14/23)

θ = 53

Best of Luck!