Answer:
Step-by-step explanation:
The same bases (9) needs the same exponents to be equal:
[tex]\big9^{2x + 1}=\big9^{3x-2}\quad\iff\quad 2x+1=3x-2\\\\2x+1=3x-2\\\\2x-3x=-2-1\\\\-x=-3\\\\x=3[/tex]
The computation of the indices show that the value of x in 9^(2x + 1) = 9^(3x – 2) is 3.
From the information given, we are told to simply solve 9^(2x + 1) = 9^(3x – 2). In this case, the exponents given are equal which is 9.
Therefore, 2x + 1 = 3x - 2
Collect like terms
3x - 2x = 1 + 2
x = 3
Therefore, the value of x is 3.
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