Answer:
see explanation
Step-by-step explanation:
15
JK + KL = JL , substitute values
2x + 1 + 6x = 81, that is
8x + 1 = 81 ( subtract 1 from both sides )
8x = 80 ( divide both sides by 8 )
x = 10
Thus JK = 2x + 2 = 2(10) + 1 = 20 + 1 = 21
KL = 6x = 6 × 10 = 60
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16
JK + KL = JL , substitute values
2x + x + 2 = 5x - 10 , that is
3x + 2 = 5x - 10 ( subtract 3x from both sides )
2 = 2x - 10 ( add 10 to both sides )
12 = 2x ( divide both sides by 2 )
6 = x
Thus
JK = 2X = 2 × 6 = 12
KL = x + 2 = 6 + 2 = 8
JL = 5x - 10 = 5(6) - 10 = 30 - 10 = 20
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17
Calculate the distance d using the distance formula
d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]
with (x₁, y₁ ) = S(7, 3) and (x₂, y₂ ) = T(1, - 5)
d = [tex]\sqrt{(1-7)^2+(-5-3)^2}[/tex]
= [tex]\sqrt{(-6)^2+(-8)^2}[/tex]
= [tex]\sqrt{36+64}[/tex]
= [tex]\sqrt{100}[/tex] = 10
