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At what temperature would one mole of molecular nitrogen (N_2) have 7.0 × 10^3 J of translational kinetic energy (total internal energy)? Note: the atomic mass of N is 14 g/mol.

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Answer:

T = 561.3K

Explanation:

The translational kinetic energy of a gas such as nitrogen is obtained using the formula:

K = 3/2 * n * R * T

Where n  are moles of gases (1mole of N₂), R is gas constant (8.314J/molK)and T is absolute temperature (in K)

If the translational energy of the gas is 7.0x10³J:

7.0x10³J = 3/2 * 1 mole * 8.314J/molK * T

T = 561.3K

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