contestada

PLEASE HELP ASAP!!!!


Which statement describes the symmetry of j(x)?

j(x) is an odd function.
j(x) is an even function.
j(x) is both an even and an odd function.
j(x) is neither an even nor an odd function.

PLEASE HELP ASAP Which statement describes the symmetry of jx jx is an odd function jx is an even function jx is both an even and an odd function jx is neither class=

Respuesta :

Answer:

j(x) is an odd function

Step-by-step explanation:

We are given;

j(x) = 220/x³ and j(-x) = 220/(-x)³

Now,

when x = 1;

j(x) = 220/1³ = 220/1 = 220

j(-x) = 220/(-1)³ = 220/-1 = -220

When x = 2;

j(2) = 220/2³ = 220/8

j(-2) = 220/(-2)³ = -220/8

Now, Algebraically, function j would be even if and only if j(-x) = j(x) for all x in the domain of j. While j is odd if and only if j(-x) = -j(x) for all x in the domain of j.

From the values gotten, we can see that :j(-x) = -j(x). Thus, we can say that j(x) is an odd function.

themountaintrolls

Answer:

A) j(x) is an odd function.

Step-by-step explanation:

Otras preguntas