Answer:
Number of tickets with ASB is 620 and number of tickets without ASB is 300.
Step-by-step explanation:
Let the number of tickets for the homecoming dance with ASB and without ASB are x and y respectively.
Total number of tickets = 920 tickets
[tex]x+y=920[/tex] ...(1)
Tickets for the homecoming dance cost $10 with ASB and $12 without ASB. Total collected amount is $9,799
[tex]10x+12y=9799[/tex] ...(2)
From (1) and (2), we get
[tex]10(920-y)+12y=9799[/tex]
[tex]9200-10y+12y=9799[/tex]
[tex]2y=9799-9200[/tex]
[tex]2y=599[/tex]
Divide both sides by 2.
[tex]y=299.5[/tex]
But number of tickets cannot be in decimal.
[tex]y\approx 300[/tex]
Put y=300 in (1).
[tex]x+300=920[/tex]
[tex]x=920-300[/tex]
[tex]x=620[/tex]
Therefore, number of tickets with ASB is 620 and number of tickets without ASB is 300.
