Answer:
[tex](f+g)(x)=x^2-2x-35[/tex]
Step-by-step explanation:
So we have the two functions:
[tex]f(x)=x^2-3x-40\text{ and } g(x)=x+5[/tex]
And we want to find (f+g)(x). This is the same as:
[tex](f+g)(x)=f(x)+g(x)[/tex]
Substitute:
[tex]=(x^2-3x-40)+(x+5)[/tex]
Combine like terms:
[tex]=x^2+(-3x+x)+(-40+5)[/tex]
Add:
[tex]=x^2-2x-35[/tex]
And we're done!
