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Three point charges are arranged on a line. Charge q3 = +5.00 nC and is at the origin. Charge q2 = -3.00 nC and is at x = 3.50 cm . Charge q1 is at x = 1.00 cm .What is q1 (magnitude and sign) if the net force on q3 is zero?

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hopemichael95

Answer:

Now using

K*q3q1/(1cm)² = kq3q2/(3.5cm)²

So

q1/1²= q2/3.5²

But q2= -3nC

So q1= (1/3.5)²* 3*10-9

q1= 0.24nC

q1 will be positive because to become the net force on the q3 charge due to the remaining two charges, the force due to each charge on the third force should be equal and opposite thus q1 is positive

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