Answer:
Magnitude of the resultant vector is R = 6.81 m
Explanation:
Given :
Vector A having magnitude of 2.5 m
Vector A having direction 37 degree south of east.
Vector B having magnitude of 3.5 m
Vector B having direction 20 degree north of east.
Therefore, the angle between the two vectors is, θ = 37+20 = 57 degree
So, the resultant of the two vectors are given by
[tex]$ R = \sqrt{A^2+B^2+2AB \cos \theta}$[/tex]
[tex]$ R = \sqrt{2.5^2+3.5^2+2(2.5)(3.5) \cos 57}$[/tex]
[tex]$ R = \sqrt{6.25+12.25+17.5 \times 0.54}$[/tex]
[tex]$ R = \sqrt{46.45}$[/tex]
R = 6.81 m
