Answer:
1
[tex]a = 2.82 \ m/s^2[/tex]
2
[tex]t = 8.87 \ s[/tex]
3
[tex]s = 204 \ m[/tex]
Explanation:
From the question we are told that
The speed of the car is [tex]v = 25.0 \ m/s[/tex]
The length of the ramp is [tex]d = 111 \ m[/tex]
The constant velocity of the traffic [tex]v_t = 23.0 \ m/s[/tex]
Generally the acceleration of the car is mathematically represented as
[tex]a = \frac{v^2 - u^2 }{2d}[/tex]
Here u is equal to zero given that the car started from rest so
[tex]a = \frac{25^2 - 0^2 }{2 * 111}[/tex]
=> [tex]a = 2.82 \ m/s^2[/tex]
Generally the time taken is mathematically represented as
[tex]t = \frac{ v - u}{ a}[/tex]
=> [tex]t = \frac{ 25 - 0}{2.82}[/tex]
=> [tex]t = 8.87 \ s[/tex]
The distance traveled by the traffic is mathematically represented as
[tex]s = v_{t}t + \frac{1}{2} a t^2[/tex]
Here a is zero given that the traffic was moving at constant speed
=> [tex]s = 23 * 8.87[/tex]
=> [tex]s = 204 \ m[/tex]
