Respuesta :

Answer:

f^-1(x) = 1/5x + 1/5

Step-by-step explanation:

Switch the x and y values:

y = 5x - 1

x = 5y - 1

Put the equation back into y = form:

x = 5y - 1

x + 1 = 5y

1/5x + 1/5 = y

y = 1/5x + 1/5

f^-1(x) = 1/5x + 1/5

Answer: y = [tex]\frac{x+1}{5}[/tex]

Step-by-step explanation:

I find it helpful if I change f(x) into y.

y = 5x - 1

Then, switch x and y

x = 5y - 1

Solve normally for y in terms of x

x+1 = 5y

[tex]\frac{x+1}{5}[/tex] = y

So, the inverse is y = [tex]\frac{x+1}{5}[/tex]

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