Answer:
11 g
Explanation:
Amount of phosphorus = 6.2g ÷ 31.0 g/mol = 0.2 mol
Amount of P2O3 formed = (0.2mol / 4) × 2 = 0.1 mol
Mass of P2O3 = 0.1mol × 110 g/mol = 11 g
The mass of phosphorous(III) produced from 6.2g of phosphorous is 11g.
Phosphorus is a chemical element which belongs to nitrogen family in the periodic table with symbol P and atomic number 15.
Mass is a measure of the amount of matter that an object contains. The base SI unit of mass is the kg.
Phosphorus reacts with oxygen to form phosphorus (III) oxide.
4P(s) + 3O2(g) --> 2P2O3(s)
Given mass of phosphorous = 6.2 g
Atomic mass of Phosphorous = 31 g
Molecular weight of phosphorous (P₂O₃)
= 31 x 2 + 16 x 3
= 110g/mol
Amount of phosphorus = 6.2g / 31 g/mol = 0.2 mol
Amount of P2O3 formed = (0.2mol / 4) × 2 = 0.1 mol
Mass of P2O3 = 0.1mol × 110 g/mol = 11 g
Hence, 11g of phosphorous (III) is produced from 6.2g of phosphorous.
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