Answer:
V = 4.6 × 10^20 m/s
Explanation:
Given that the magnitude of the drift speed V in a wire that carries a current I of 1A. The wire has radius 2mm and the number of electrons per unit volume of free electrons is n= 10 28 m -3 Cross-sectional area of the wire is A = πr 2
Convert the radius from mm to m by dividing it by 1000. Substitute it in the below formula
The cross sectional area A = π × (0.002)^2
A = 1.257 × 10^-5 m^2
The formula to use is:
I = VneA
Substitutes all the parameters into the formula
1 = V × 10^23 × 1.67×10^-19 × 1.257×10^-5
1 = 2.16 × 10^-21V
V = 1 / 2.16 × 10^-21
V = 4.6 × 10^20 m/s
