Answer:
2 real roots
Step-by-step explanation:
Given a quadratic equation in standard form
ax² + bx + c = 0 ( a ≠ 0 )
Then the nature of the roots are found using the discriminant
Δ = b² - 4ac
• If b² - 4ac > 0 then 2 real and distinct roots
• If b² - 4ac = 0 then 2 real and equal roots
• If b² - 4ac < 0 then 2 complex roots
x² + 4x - 1 = 0 ← is in standard form
with a = 1, b = 4, c = - 1, then
b² - 4ac = 4² - (4 × 1 × - 1 ) = 16 + 4 = 20
Since b² - 4ac > 0 then the equation has 2 real and distinct roots
