Answer:
The cannonball lands 29,348 m away from the launching point.
Explanation:
Projectile Motion
It's known as the type of motion that experiences an object that is projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.
Being vo the initial speed of the object, θ the initial launch angle, and g=9.8m/s^2 the acceleration of gravity, then the maximum horizontal distance traveled by the object (also called Range) is:
[tex]\displaystyle d={\frac {v_o^{2}\sin(2\theta )}{g}}[/tex]
The cannonball is fired with a velocity vo= 589 m/s and is aimed θ=28° above the ground. Substituting the numerical values:
[tex]\displaystyle d={\frac {589^{2}\sin(2*28 )}{9.8}}=29,348\ m[/tex]
The cannonball lands 29,348 m away from the launching point.
