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A person throws a ball from height of 6 feet with an initial
vertical velocity of 48 feet per second. Use the vertical motion
model, h = - - 16t2 + vt +s, where v is the initial velocity in
feet per second and s is the height in feet, to calculate the
amount of time the ball is in the air before it hits the ground
again. Round your answer to the nearest tenth if necessary.
time in air: _____ seconds

Respuesta :

cookingspraypm

Answer:

3.1 s

Explanation:

use the quadratic formula

x = −b + √(b2 − 4ac)/2a

where a=-16 b=48 (the velocity) and c=6 (the height)

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