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If a 110 kg go-cart traveling at 13.41 m/s has a collision and experiences an impulse of 615 N for 1 s, what is its change in velocity?

Respuesta :

Answer:

5.59 m/s

Explanation:

We are given;

Mass = 110 kg

Initial velocity: u = 13.41 m/s

Force = 615 N

Time(t) = 1 s

Now, formula for force is;

Force = mass x acceleration

Thus;

615 = 110 × acceleration

Acceleration(a) = 615/110 = 5.591 m/s²

Now, using Newton's first law of motion, we can find acceleration (a). Thus;

v = u + at

v = 13.41 + (5.591 × 1)

v ≈ 19 m/s

So, change in velocity is;

Final velocity(v) - Initial velocity(u) = 19 - 13.41 = 5.59 m/s

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