Answer:
Sucrose, CaCl2 = A
Water = B
Protein = C
Explanation:
Why we have a net movement out of the tube?
Because the osmotic pressure is higher out the tube.
That is due because of the greater presence of osmotically actice compounds.
Take a look:
Tube:
4% of CaCl2 > ([tex]Ca^+ + 2Cl^-[/tex])x 0,04
9% of Sucrose > (Sucrose)x 0,09 - Sucrose does not dissociate or ionize
10% of Protein > Does not matter it quantity, because she it's not a osmotic compound.
Solution:
10% of CaCl2 > ([tex]Ca^+ + 2Cl^-[/tex]) x 0,1
10% of Sucrose > (Sucrose) x 0,1
As both CaCl2 and Sucrose are in a higher concentration, we can understand that the osmotic pressure is greater in the Solution side, making the solution of the tube to migrate to her.
But maybe talk does not help. In the annex you can see a drawing of a possibility for this situation.
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EDIT: I just saw that your question wasn't asking exatcly what I was trying to solve.
But anyway, by the same motives I already said, the answers are:
Sucrose and CaCl2 are going from the down tube - I know it does not sound possible, but imagine that they are really close ore even that they are side to side in the ground -, to the upper tube. That happens because of the EF that I said.
In the other side, water are leaving the uper tube, to equilibrate the concentration of compouns in both systems.
The protein can't move toward any tube, because as the question said, it is far bigger than the spots in the semipermeable membrane.
Also, it doest not has sufficiently interaction trough the other compounds.
Final answer:
Sucrose, CaCl2 = A
Water = B
Protein = C
