Answer:
F = 695.25 N
Explanation:
The force between Mars and Rover can be given by Newton's Law of Gravitation can be written as follows:
F = Gm₁m₂/r²
where,
F = Force of Gravity = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
m₁ = mass of rover = 74 kg
m₂ = mass of mars = 6.39 x 10²³ kg
r = distance between the centers of mars and rover = 2.1299 x 10⁶ m
Therefore,
F = (6.67 x 10⁻¹¹ N.m²/kg²)(74 kg)(6.39 x 10²³ kg)/(2.1299 x 10⁶ m)²
F = 695.25 N
