Answer:
8.22m
Explanation:
As interpreted from this problem, the angle of launch is 90 degrees as it is thrown straight up. Given an angle launch of 90°, upward initial velocity of 12.7m/s, and initial height of 0m. A much simpler equation can be used to find the maximum height.
[tex]h_{max} = h_ {0} + \frac{{v_0}^{2} }{2g}[/tex]
this means that the max height is equal to the initial height plus the initial velocity squared divided by 2 times the acceleration of earth's gravity(≈9.8m/s^2 or 10m/s^2 depending on how you fix it).
when substituted into the equation, you should get.
(9.8m/s^2)
hmax = 0 + ((12.7)^2)/(2*9.8)
hmax = 161.29/19.6 ≈ 8.22
hmax = 8.22m
