Answer:
Below.
Step-by-step explanation:
m < PCA = m < CAD ( alternate angles)
m < BAD = m <CAD ( given)
Also m < CAB = m < PCA + m < CPA ( exterior angle of a triangle theorem).
Also m < CAB = m< CAD + m < BAD (given)
So m < PCA + m < CPA = m < CAD + m < BAD
But m < PCA = m < CAD
so m < CAD + m < CPA = m < CAD + m BAD
So m < CPA = m < BAD
But m < PCA = m < CAD = m BAD
therefore m < CPA = m < PCA
That makes triangle CAP isosceles
Therefore AP = AC.
